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The work done in increasing the radius o...

The work done in increasing the radius of a soap bubble from 4 cm to 5 cm is Joule (given surface tension of soap water to be `25xx10^(-3)N//m)`

A

`0.5657xx10^(-3)`

B

`5.657 xx10^(-3)`

C

`56.5 xx10^(-3)`

D

`565 xx10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`W=8pi(r_(2)^(2)-r_(1)^(2))T`
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