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A tube of length L and radius R is joine...

A tube of length L and radius R is joined to another tube of length `(L)/(3)` and radius `(R)/(2)`. A fluid is flowing through this joint tube. If the pressure difference across the first tube is `P` then pressure difference across the second tube is

A

`16P//3`

B

`4P//3`

C

P

D

`3P//16`

Text Solution

Verified by Experts

The correct Answer is:
A
`(P_(1))/(P_(2))=(R_(1))/(R_(2))=(((8nl_(1))/(pir_(1)^(4))))/(((8nl_(2))/(pir_(2)^(4))))`
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