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A soap film in formed on a frame of area...

A soap film in formed on a frame of area `4xx10^(-3)m^(2)`. If the area of the film in reduced to half, then the change in the potential energy of the film is (surface tension of soap solution`=40xx10^(-3)N//m)`

A

`32xx10^(-5)J`

B

`16xx10^(-5)J`

C

`8xx10^(-5)J`

D

`16xx10^(5)J`

Text Solution

Verified by Experts

The correct Answer is:
B
`PE_(1)=W_(1)=2TA`
`PE_(1)=W_(2)=2T((A)/(2))`. Find out `DeltaPE`
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