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A small block of wood of relative densit...

A small block of wood of relative density 0.5 is submerged in water at a depth of 5 m When the block is released it starts moving upwards, the acceleration of the block is `(g=10ms^(-2)`)

A

`5 ms^(-2)`

B

`10 ms^(-2)`

C

`7.5 ms^(-2)`

D

`15 ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`ma_("apparent")=" force of buoancy"-"weight of body"`
`=Vd_(w)g-Vd_(B)g`
`rArr a_("apparent")=(Vd_(w)g-Vd_(B)g)/(Vd_(B))=g((d_(w))/(d_(B))-1)`
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