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A sphere of solid material of relative d...

A sphere of solid material of relative density 9 has a concentric spherical cavity and sinks in water. If the radius of the sphere be R. Then the radius of the cavity (r) will be related to R as

A

`r^(3)=(8)/(9)R^(3)`

B

`r^(3)=(2)/(3)R^(3)`

C

`r^(3)=(sqrt8)/(3)R^(3)`

D

`r^(3)=sqrt((2)/(3))R^(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`(V_("cavity"))/(V_(s))=(V_(s)-V_("metal"))/(V_(s))=1-(V_("metal"))/(V_(s))=1-(d_(w))/(d)=1-(1)/(S.G)`
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