Home
Class 11
PHYSICS
A large open top container of negligible...

A large open top container of negligible mass and uniform cross sectional area `A` has a small uniform cross sectional area `a` in its side wall near the bottom. The container is kept over a smooth horizontal floor and contains a liquid of density `rho` and mass `m_(0)`. Assuming that the liqud starts flowing through the hole A the acceleration of the container will be

A

`(2ag)/(A)`

B

`(ag)/(A)`

C

`(2Ag)/(a)`

D

`(Ag)/(a)`

Text Solution

Verified by Experts

The correct Answer is:
A

`F=ma., rhoa v^(2)=ma., rho a(2gh)=ma.`
`a.=(2rhoagh)/(m)=(2rhoagh)/(rhoAh)=(2ag)/(A)`
Promotional Banner

Topper's Solved these Questions

  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise EXERCISE - II (H.W) (POISEUILLE.S EQUATION)|6 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise EXERCISE - II (H.W) (PORCE DUE TO SURFACE TENSION)|4 Videos
  • MECHANICAL PROPERTIES OF FLUIDS

    NARAYNA|Exercise EXERCISE - II (H.W) (EQUATION OF CONTINUITY, BERNOULLI.S THEOREM AND ITS APPLICATIONS)|2 Videos
  • MATHEMATICAL REVIEW & PHYSICAL WORLD

    NARAYNA|Exercise C.U.Q|13 Videos
  • MECHANICAL PROPERTIES OF SOLIDS

    NARAYNA|Exercise LEVEL-II (H.W)|24 Videos

Similar Questions

Explore conceptually related problems

A large open top container of negligible mass and uniform cross sectional area A a has a small hole of cross sectional area A//100 in its side wall near the bottom. The container is kept on a smooth horizontal floor and contains a liquid of density rho and mass M_(0) . Assuming that the liquid starts flowing out horizontally through the hole at t=0 , calculate a the acceleration of the container and its velocity when 75% of the liquid has drained out.

A large open top container of negligible mass and uniform cross-sectional area A has a small hole of croos-sectional area (A)/(100) in its side wall near the bottom.The container is kept on a smooth horizontal floor and contains a liquid of density rho and mass m_(0) . Assuming that the liquid starts flowing out horizontally through the hole at t = 0 , The acceleration of the container is (x)/(10) m//s^(2) than x is -

A large container (with open top) of negligible mass and uniform cross-sectional area A has a small hole of cross-sectional area a in its side wall near the bottom. The container contains a liquid of density rho and mass m. If the liquid starts flowing out of the hole at time t = 0, the velocity of efflux of the liquid when 75% of the liquid has drained out is:

A fixed container of height H with large cross-sectional area A is completely filled with water. Two small orifice of cross-sectional area a are made, one at the bottom and the other on the vertical side of the container at a distance H/2 from the top of the container find the time taken by the water level to reach a height of H/2 from the bottom of the container.

A cylindrical massless container of cross sectional area A have a fluid filled up to height h and have a small orifice of area a in wall near its bottom. Find minimum coefficient between container and ground so that container does not move

There are two holes, each of cross-sectional area a, on the opposite side of a wide rectangular tank containing a liquid of density rho . When the liquid flows out of the holes, find the net force on the tank. Given h is the vertical distance between two holes.

A container of cross-section area A resting on a horizontal surface, holds two immiscible and incompressible liquid of densities rho and 2 rho as shown in figure. The lower density liquid is open to the atmosphere having pressure P_(0) . The pressure at the bottom of the container is

There are two holes, each of cross-sectional area a, on the oppisite side of a wide rectangular tank containing a liquid of density rho . When the liquid flows out of the holes the net force on the tank is [ h is the vertical distance between the two holes].