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The excess pressure in soap bubble is 10...

The excess pressure in soap bubble is `10(N)/(m^(2))` if eight soap bubble are combined to form a big soap bubble excess pressure in big bubble is (in `(N)/(m^(2)))`

A

5

B

10

C

20

D

2.5

Text Solution

Verified by Experts

The correct Answer is:
A
`(4)/(3)piR^(3)=n(4)/(3)pir^(3), R=2r, p=(4T)/(R )rArr (P_("big"))/(P_("small"))=(r )/(R )`
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Knowledge Check

  • The excess pressure inside a soap bubble is

    A
    inversely proportional to the surface tension
    B
    inversely proportional to its radius
    C
    directly proportional to square of its radius
    D
    inversely proportional to square of its radius

  • The pressure inside a soap bubble is

    A
    equal to atmospheric pressure,
    B
    less then atmospheric pressure,
    C
    greater than atmospheric pressure,
    D
    just double of atmospheric pressure.

  • Excess of pressure inside a soap bubble is

    A
    inversely proportional to its radius
    B
    directly proportional to its radius
    C
    directly proportional to square root of its radius
    D
    independent of its radius