The excess pressure in soap bubble is 10...

The excess pressure in soap bubble is `10(N)/(m^(2))` if eight soap bubble are combined to form a big soap bubble excess pressure in big bubble is (in `(N)/(m^(2)))`

2.5

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The correct Answer is:

`(4)/(3)piR^(3)=n(4)/(3)pir^(3), R=2r, p=(4T)/(R )rArr (P_("big"))/(P_("small"))=(r )/(R )`

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The excess pressure inside a soap bubble is

inversely proportional to the surface tension

inversely proportional to its radius

directly proportional to square of its radius

inversely proportional to square of its radius

equal to atmospheric pressure,

less then atmospheric pressure,

greater than atmospheric pressure,

just double of atmospheric pressure.

inversely proportional to its radius

directly proportional to its radius

directly proportional to square root of its radius

independent of its radius