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A cannon and a target are 5.10 km apart ...

A cannon and a target are `5.10 km` apart and located at the same level. How soon will the shell launched with the initial velocity `240 m//s` reach the target in the absence of air drag?

Text Solution

Verified by Experts

Here, `u_(0)=240 "ms"^(-1), R=5.10" km"`=5100m,
`g=9.8" ms"^(-2),alpha=?` `sin 2alpha=(Rg)/(u_(0)^(2)) rArr alpha=30^(@)" or "60^(2)`
using, `T=(2u_(0) sin alpha)/(g)`
When `alpha=30^(@), T_(1)=(2xx240xx0.5)/(9.8)=24.5s`
When `a=60^(@), T_(2)=(2xx240xx0.867)/(9.8)=42.46s`
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