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The ceiling of a long hall is 20 m high....

The ceiling of a long hall is `20 m` high. What is the maximum horizontal distance that a ball thrown with a speed of `40 m` can go without hitting the ceiling of hall `(g=10 ms^(-2))` ?

Text Solution

Verified by Experts

Here, H=20, u=40 `ms^(-1)`.
Suppose the ball is thrown at an angle `theta` with the horizontal.
Now `H=(u^(2) sin^(2) theta)/(2g) rArr 20=((40)^(2) sin^(2) theta)/(2xx10)`
or, `sin theta=0.5 rArr theta=30^(@)`
Now `R=(u^(2) sin 2 theta)/(g)=((40)^(2)xxsin 60^(@))/(10)`
`=((40)^(2)xx0.866)/(10)=138.56` m
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