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In the absence of wind the range and max...

In the absence of wind the range and maximum height of a projectile were `R` and `H`. If wind imparts a horizontal acceleration `a=g//4` to the projectile then find the maximum range and maximum height.

Text Solution

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`H^(1)=H (therefore . u sin theta` remains same)
`T_(1)=T`
`R^(1)=u_(x)T+(1)/(2)aT^(2)=R+(1)/(2)(g)/(4)T^(2)`
`=R+(1)/(8)gT^(2)" "R+H`
`R^(1)=R+H" " H^(1)=H`
If a body is projected with a velocity
`overset(vecu)=overset(veci)+overset(vecj)+overset(veck)`
`(hati-" east "hatj-"north "overset(frown)(k)-"vertical")^("then")`
`u_(x)=sqrt(a^(2)+b^(2)) , u_(y)=c`
`T=(2c)/(g), H=(c^(2))/(2g), R=(2(sqrt(a^(2)+b^(2))c))/(g)`
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