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A golfer standing on the ground hits a b...

A golfer standing on the ground hits a ball with a velocity of `52 m//s` at an angle `theta` above the horizontal if `tan theta=5/12` find the time for which the ball is at least `15m` above the ground?
`(g=10m//s^(2))`

Text Solution

Verified by Experts

`v_(y)=sqrt(u_(y)^(2)-2gy), u_(y)=u sin theta`
`v_(y)=sqrt(52xx52xx(5xx5)/(13xx13)-2xx10xx15)`
`=sqrt(16xx25-300)=10`
`Deltat=(2v_(y))/(10)=(2xx10)/(10)=2s`
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