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A projectile has the maximum range of 50...

A projectile has the maximum range of `500m`. If the projectile is now thrown up on an inclined plane of `30^(@)` with the same speed, what is the distance covered by it along the inclined plane?

Text Solution

Verified by Experts

`R_("max")=(u^(2))/(g)`
`:. 500=(u^(2))/(g) " or "u=sqrt(500g)`
`v^(2)-u^(2)=2as`
`0-500g=2xx(-g sin 30^(@))x`
`x=500m`.
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