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When a motor cyclist takes a U-turn in 4...

When a motor cyclist takes a `U-turn` in `4s` what is the average angular velocity of the motor cyclist.

Text Solution

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When the motor cyclist takes a U-turn, angular displacement, `theta pi`rad and t=4 s.
The average angular velocity,
`omega=(theta)/(t)=(pi)/(4)=0.7855"rad"S^(-1)`
Note: In general we can also use the following equations to solve the problems
`omega_(av)=(Deltatheta)/(Deltat), alpha_(av)=(Deltaomega)/(Deltat)`
`omega=(d theta)/(d theta), alpha=(d theta)/(dt)=(d^(2)theta)/(dt^(2))=omega(d omega)/(d theta)`
`int d theta=int omega dt`
`int d omega=int alpha dt`
`int alpha d theta=int omega d theta`
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