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A particle is projected in xy plane with...

A particle is projected in `xy` plane with `y`-axis along vertical, the point of projection is origin. The equation of the path is `y=sqrt3x-g/2x^(2)`.where `y` and `x` are in `m`.Then the speed of projection in `ms^(-1)` is

A

2

B

`sqrt(3)`

C

4

D

`(sqrt(3))/(2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Compare the equation with `y=x tan theta -(g)/(2u^(2) cos^(2) theta) x^(2)`
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