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The potential energy of a projectile at ...

The potential energy of a projectile at its maximum height is equal to its kinetic energy there. If the velocity of projection is `20 m//s^(-1)`,its time of flight is `(g=10 m//s^(2))`

A

2s

B

`2sqrt(2)s`

C

`(1)/(2) s`

D

`(1)/(sqrt(2))s`

Text Solution

Verified by Experts

The correct Answer is:
B
`P.E =K.E rArr (1)/(2) mu^(2) sin^(2) theta =(1)/(2) mu^(2) cos^(2) theta`
use `T=(2u sin theta)/(g)`
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