Home
Class 11
PHYSICS
The horizontal and vertical displacement...

The horizontal and vertical displacements of a projectile are given as `x=at` & `y=bt-ct^(2)`.Then velocity of projection is

A

`sqrt(a^(2)+b^(2))`

B

`sqrt(b^(2)+c^(2))`

C

`sqrt(a^(2)+c^(2))`

D

`sqrt((b^(2)-c^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`u_(x) =(dx)/(dt), u_(y) =(dy)/(dt) and u = sqrt(u_(x)^(2) +u_(y)^(2))`
Promotional Banner

Similar Questions

Explore conceptually related problems

The horizontal and vertical displacements of a projectile at time t are x=36t and y=48t-4.9t^(2) respectively where x ,y are in meters and t in seconds.Initial velocity of the projectile in m/s is

The horizontal and vertical distances covered by a projectile at tiem t are given by x=at and y= bt^(2)+ct , wehre a,b and c are constants. What is the magnitude of the velocity of the projectile 1 second after it is fired?

The horizontal and vertical displacements x and y of a projectile at a given time t are given by x= 6 "t" and y= 8t -5t^2 meter.The range of the projectile in metre is:

A body is projected horizontally from a point above the ground. The motion of the body is described by the equations x = 2 t and y= 5 t^2 where x and y are the horizontal and vertical displacements (in m) respectively at time t. What is the magnitude of the velocity of the body 0.2 second after it is projected?

The horizontal and vertical displacements of a particle moving along a curved line are given by x=5t and y = 2t^2 + t. Time after which its velocity vector makes an angle of 45^@ with the horizontal is

The point from where a ball is projected is taken as the origin of the coordinate axes. The x and y components of its displacement are given by x=6t and y=7t-5t^(2) . What is the velocity of projection?

A ball is projected from the origin. The x- and y-coordinates of its displacement are given by x = 3t and y = 4t - 5t^2 . Find the velocity of projection ("in" ms^(-1)) .

The height y and distance x along the horizontal plane of a projectile on a certain planet are given by x = 6t m and y = (8t^(2) - 5t^(2))m . The velocity with which the projectile is projected is

The trajectory of a projectile in a vertical plane is y=ax-bx^(2) , where a and b are constants and x and y are respectively horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projection form the horizontal are:

The trajectory of a projectile in a vertical plane is y = ax - bx^2 , where a and b are constant and x and y are, respectively, horizontal and vertical distances of the projectile from the point of projection. The maximum height attained by the particle and the angle of projectile from the horizontal are.