Home
Class 11
PHYSICS
If vecu=ahati+bhatj+chatk with hati,hatj...

If `vecu=ahati+bhatj+chatk` with `hati,hatj,hatk`are in east, north and vertical directions, the maximum height of the projectileis

A

`(a^(2))/(2g)`

B

`(b^(2))/(2g)`

C

`(c^(2))/(2g)`

D

`(b^(2)c^(2))/(2g)`

Text Solution

Verified by Experts

The correct Answer is:
C
`u_(x) =sqrt(a^(2)+b^(2)), u_(y) = u sin theta =c`
Promotional Banner

Similar Questions

Explore conceptually related problems

If vecu=ahati+bhatj+chatk with hati,hatj,hatk are in east, north and vertical directions, horizontal component of velocity of projectile is

A ball is projected from the top of a tower with a velocity 3hati+4hatj+5hatk ms^(-1) ,where hati+hatj+hatk are unit vectors along east, north and vertical upwards respectively. If the height of the tower is 30 m , its range is (g=10 ms^(-1))

A ball is projected from the top of a tower with a velocity 3hati+4hatj+5hatk ms^(-1) ,where hati+hatj+hatk are unit vectors along east, north and vertical upwards respectively. If the height of the tower is 30 m , its time is (g=10ms^(-1))

If veca=hati+2hatj-hatk and vecb=3hati+hatj-hatk find a unit vector int direction of veca-vecb .

Two vectors P=2hati+bhatj+2hatk and Q=hati+hatj+hatk will be parallel if

Let vecV = 2hati +hatj - hatk and vecW= hati + 3hatk . if vecU is a unit vector, then the maximum value of the scalar triple product [ vecU vecV vecW] is

The vectors 2hati+hatj-4hatk and ahati+bhatj+chatk are perpendicular, if

Let vecV=2hati+hatj-hatk and vecW=hati+3hatk . It vecU is a unit vector, then the maximum value of the scalar triple product [(vecU, vecV, vecW)] is

Let vecV=2hati+hatj-hatk and vecW=hati+3hatk. If vecU is a unit vector then the maximum value of the scalar triple product [vecU vecV vecW] is (A) -1 (B) sqrt(10)+sqrt(6) (C) sqrt(59) (D) sqrt(60)