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The horizontal and vertical distances tr...

The horizontal and vertical distances travelled by a particle in time t are given by x=6t and `y=8t-5t^(2)`. If g=`10m//sec^(2)`, then the initial velocity of the particle is

A

`8 ms^(-1)`

B

`6 ms^(-1)`

C

`14 ms^(-1)`

D

`10 ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`u = sqrt((g(1+A^(2)))/(2B))`
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