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An object is projected with a velocity o...

An object is projected with a velocity of `20(m)/(s)` making an angle of `45^@` with horizontal. The equation for the trajectory is `h=Ax-Bx^2` where h is height, x is horizontal distance, A and B are constants. The ratio A:B is (g`=ms^-2)`

A

`1:5`

B

`5:1`

C

`1:40`

D

`40:1`

Text Solution

Verified by Experts

The correct Answer is:
D
`A = tan theta, B =(g)/(2u^(2) cos^(2) theta)`
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