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For a projectile, the ratio of maximum h...

For a projectile, the ratio of maximum height reached to the square of flight time is `(g = 10 ms^(-2))`

A

`5:4`

B

`5:2`

C

`5:1`

D

`10:1`

Text Solution

Verified by Experts

The correct Answer is:
A
`H =(u^(2) sin^(2) theta)/(2g), T=(2u sin theta)/(g)`
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