Home
Class 11
PHYSICS
A body is projected with velocity u such...

A body is projected with velocity `u` such that in horizontal range and maximum vertical heights are samek.The maximum height is

A

`(u^(2))/(2g)`

B

`(3u^(2))/(4g)`

C

`(16 u^(2))/(17g)`

D

`(8u^(2))/(17g)`

Text Solution

Verified by Experts

The correct Answer is:
C

`Tan theta =(4H)/(R )`
`R=H_(max)`
`therefore Tan theta =4`

`H_(max) =(u^(2) sin^(2) theta)/(2g)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A body is projected with velocity u so that its horizontal range is twice the maximum height.The range is

A ball is projected from the ground with velocity u such that its range is maximum Then

A body is projected obliquely from the ground such that its horizontal range is maximum.If the change in its maximum height to maximum height, is P , the change in its linear momentum as it travels from the point of projection to the landing point on the ground will be

A projectile is fired with a velocity u in such a way that its horizontal range is three times the maximum height aatained . Find the value of horizontal range .

A particle is projected with velocity u at angle theta_(1) with horizontal .The ratio of range and maximum height is 4. When it is projected at angle theta_(2) with horizontal with same speed,the ratio of range and maximum height is 2.Then (tan theta_(1))/(tan theta_(2)) will be equal to

Find the angle of projection at which horizontal range and maximum height are equal.

A body is projected obliquely from the ground such that its horizontal range is maximum. If the change in its linear momentum, as it moves from half the maximum height to maximum height, is P, the change in its linear momentum as it travels from the point of projection to the landing point on the ground will be:

Find the angle of projection for which the horizontal range and the maximum height are equal.

A body is projected with a velocity 30 ms^(-1) at an angle of 30^@ with the vertical. Find (i) the maximum height (ii) time of flight and (iii) the horizontal range of the projectile. Take g=10 m//s^@ .

A body is projected with a velocity of 30 ms^(-1) at an angle of 30^(@) with the vertical. Find the maximum height, time of flight and the horizontal range.