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A stone is thrown with a velocity v at a...

A stone is thrown with a velocity `v` at an angle `theta` with the horizontal.Its speed when it makes an angle `beta` with the horizontal is

A

`v cos theta`

B

`(v)/(cos beta)`

C

`v cos theta cos beta`

D

`(v cos theta)/(cos beta)`

Text Solution

Verified by Experts

The correct Answer is:
A
`V cos theta =V^(1) cos beta therefore V^(1) =(V cos theta)/(cos beta)`
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