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A bomber flying upward at an angle of 53...

A bomber flying upward at an angle of `53^(@)` with the vertical releases a bomb at an altitude of `800 m`.The bomb strikes the ground `20 s` after its release.If `g=10ms^(-2)`, the velocity at the time of release of the bomb in `ms^(-1)` is

A

400

B

800

C

100

D

200

Text Solution

Verified by Experts

The correct Answer is:
C
`u cos theta =1, u sin theta =2`
use equation of the projectile
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