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Two particles move in a uniform gravitat...

Two particles move in a uniform gravitational field with an acceleration `g`.At the initial moment the particles were located at same point and moved with velocities `u_(1)=9 ms^(-1)` and `u_(2)=4 ms^(-1)` horizontally in opposite directions.The time between the particles at the moment when their velocity vectors are mutually perpendicular in `s` in (take `g=10 ms^(-2)`)

A

0.36

B

3.6

C

0.6

D

6

Text Solution

Verified by Experts

The correct Answer is:
C
`V=" at ", V=u cos theta, H=(u^(2) sin^(2) theta)/(2g)`
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