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A particle moves on a circle of radius r...

A particle moves on a circle of radius r with centripetal accelration as function of time as `a_(c)=K^(2)rt^(2)` where k is a positive constant , find the resu ltant acceleration.

A

`kt^(2)`

B

kr

C

`kr sqrt(k^(2) t^(4)+1)`

D

`kr sqrt(k^(2)t^(2)-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
From given equation `omega = kt,`
`alpha =(d omega)/(dt) =k, a_(1)=r alpha, a= sqrt(a_(c)^(2)+a_(t)^(2))`
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