Home
Class 11
PHYSICS
A stone is projected with a velocity 20s...

A stone is projected with a velocity `20sqrt2 m//s` at an angle of `45^(@)` to the horizontal.The average velocity of stone during its motion from starting point to its maximum height is

A

`10 sqrt(5)` m/s

B

`20 sqrt(5)` m/s

C

`5 sqrt(5)` m/s

D

20 m/s

Text Solution

Verified by Experts

The correct Answer is:
A

`v=(u)/(2) sqrt(1+3 cos^(2) theta)`
Promotional Banner

Similar Questions

Explore conceptually related problems

A stone is projected with a velocity 10sqrt(2)m/s^(-1) at an angle of 45^(@) to the horizontal ground.The average velocity of stone during its time of flight is (A) 10m/s^(-1) (B) 10sqrt(5)m/s^(-1) (C) 5sqrt(5)m/s^(-1)(D) 20m/s ^(-1)

A ball is projected with 20sqrt2 m//s at angle 45^(@) with horizontal.The angular velocity of the particle at highest point of its journey about point of projection is

A particle is projected with a velocity 10 m//s at an angle 37^(@) to the horizontal. Find the location at which the particle is at a height 1 m from point of projection.

A particle is projected with a velocity of 20sqrt(3) m s^(-1) at an angle of 60^(@) to the horizontal.At the moment,the direction of motion of the projectile is perpendicular to the direction of initial velocity of projection, its velocity is?

A particle is projected with a velocity of 20sqrt(3) ms^(-1) at an angle of 60^(@) to the horizontal. At the moment, the direction of motion of the projectile is perpendicular to the direction of initial velocity of projection, its velocity is

A body is projected at angle of 45^(@) to the horizontal . What is its velocity at the highest point ?

A body is projected with an initial velocity 20 m//s at 60^(@) to the horizontal. Its initial velocity vector is "___" (g=10 m//s^(2))

A particle is projected with velocity 10m/s at an angle of 45^(@) with the horizontal from some height. Consider point of projection as origin and motion in xy plane. Then (vecg=10hatj m//s^(2))

A particle is project from ground with a speed of 6 m//s at an angle of cos^(-1)(sqrt((7)/(27))) with horizontal. Then the magnitude of average velocity of particle from its starting point to the highest point of its trajectory in m//s is: