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A particle is projected with speed u at ...

A particle is projected with speed `u` at angle `theta` to the horizontal. Find the radius of curvature at highest point of its trajectory

A

`(u^(2) cos^(2) theta)/(2g)`

B

`(sqrt(3) u^(2) cos^(2) theta)/(2g)`

C

`(u^(2) cos^(2) theta)/(g)`

D

`(sqrt(3)u^(2) cos^(2) theta)/(g)`

Text Solution

Verified by Experts

The correct Answer is:
C
`r=(u^(2) cos^(2) theta)/(g)`
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