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A partricle of mass m is projected with ...

A partricle of mass m is projected with a velocity v at an angle of `60^(@)` with horizontal When the particle is at the maximum height. The magnitude ofits angular momentum about the point ofprojection is

A

zero

B

`(3 mv^(2))/(16 g)`

C

`(sqrt(3) mv^(3))/(16 g)`

D

`(3 mv^(3))/(16 g)`

Text Solution

Verified by Experts

The correct Answer is:
B
Maximumheight, `H=(v^(2)sin^(2)60^(@))/(2g)`
`=(v^(2))/(2g)xx(3)/(4)=(3v^(2))/(8g)`
Momentumofparticle at highest point
`pi= mv cos 60^(@)=(mv)/(2)`
Angular momentum=pH
`=(mv)/(2)xx(3v^(2))/(8g)`
`=(3mv^(3))/(16g)`
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