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A particle moves in a circle of radius 5...

A particle moves in a circle of radius 5 cm with constant speed and time period `0.2pis`. The acceleration of the particle is

A

`25 m//s^(2)`

B

`36 m//s^(2)`

C

`5 m//s^(2)`

D

`15 m//s^(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
Given `r=5 cm=5xx10^(-2) m and T=0.2 pis`
We know that acceleration
`a= r omega^(2)`
`=(4pi^(2))/(T^(2))r`
`=(4pixx^(2)xx5xx10^(-2))/((0.02pi)^(2))=5 ms^(-1)`
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