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The range of a projectile when fired at ...

The range of a projectile when fired at `75^(@)` with the horizontal is 0.5km. What will be its range when fired at `45^(@)` with same speed:-

A

0.5 m

B

1.0 km

C

1.5 km

D

2.0 km

Text Solution

Verified by Experts

The correct Answer is:
B
`R_(1)=(u^(2) sin theta)/(g)=(u^(2) sin 2xx)(g)`
`=(u^(2))/(g) sin 150^(@)=(u^(2))/(g) sin (180^(@)-30^(@))`
`=(u^(2))/(g) sin 30^(@)=(u^(2))/(2g)`
`R_(2)=(u^(2))/(g) sin 90^(@)=(u^(2))/(g)`
`R_(2)=2R_(1)=0.5xx2=1.0 km`
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