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For angle of projection of a projectile ...

For angle of projection of a projectile at angles and `(45^(@)+theta)`, the horizontal range described by the projectile are in the ratio of

A

`2:1`

B

`1:1`

C

`2:3`

D

`1:2`

Text Solution

Verified by Experts

The correct Answer is:
B
Horizontal range, `R=(u^(2)sin 2theta)/(g)`
For angle ofprojection `(45^(@)-theta)`.the horizontal range is
`R_(1)=(u^(2)sin [2(45^(@)-theta)])/(g)=(u^(2)sin(90^(@)-2theta))/(g)=(u^(2)cos 2 theta)/(g)`
`:.(R_(1))/(R_(2))=(u^(2)cos 2 theta//g)/(u^(2)cos 2 theta//g)=(1)/(1)`
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