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The horizontal range and the maximum hei...

The horizontal range and the maximum height of a projectile are equal. The angle of projection of the projectile is

A

`theta =tan^(-1)(2)`

B

`theta =45^(@)`

C

`theta =tan^(-1) ((1)/(4))`

D

`theta = tan^(-1) (4)`

Text Solution

Verified by Experts

The correct Answer is:
D
`(vecv)"att" 10 secvec u+vecat=(2hati+3hatj)+(0.3hati+0.2hatj)xx10=5hati+5hatj`
`:.` Magnitude `= sqrt((5^(2)+5^(2))= 5 sqrt(2)` units
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