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a projectile is fired from the surface o...

a projectile is fired from the surface of the earth with a velocity of `5ms^(-1)` and angle `theta` with the horizontal. Another projectile fired from another planet with a velocity of `3ms^(-1)` at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in `ms^(-2)` is given `(g=9.8 ms^(-2))`

A

`3.5`

B

`5.9`

C

`16.3`

D

`110.8`

Text Solution

Verified by Experts

The correct Answer is:
A
The equation oftrajectory is `y=x tan theta-(gx^(2))/(2u^(2) cos^(2) theta)`
where `theta` s the angle ofprojectilon and u is the velocity with which projectile is projected
For equal trajectories for same angle of projection `(g)/(u^(2))` = constant
Asper question `(9.8)/(5^(2))=(g_(1))/(3^(2))`
Where `g^(1)` is acceleration due to gravity on the planet
`g^(1)=(9.8xx9)/(2.5)3.5 ms^(-2)`
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