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A stone is projected from a horizontal p...


A stone is projected from a horizontal plane. It attains maximum height `H` & strikes a stationary smooth wall & falls on the ground vertically below the maximum height. Assuming the collision to be elastic the height of the point on the wall where ball will strike is

A

(H/2)

B

(H/4)

C

(3H/4)

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C

Due to collision, vertical component of velocity of stone does not change. So, time to reach the ground here is equal to time of flight of oblique projectile, i.e, `T=(2u sin thetya)/(g)=(2 omega)/(g)`
Because colision is elastic, even horizontal com ponent renmains same except for getting reversed. If the time taken from B to C is t, then time taken from O to A is 2 t and from A to Bis t
FromA to B and then to reach at point C:

`H=(1)/(2)g(2t^(2))=2g^(2)`
In the fugure, `a=(1)/(2) "gt"^(2)=(H)/(4)`
`:.h=H-alpha-(H)/(4)=(3H)/(4)`
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