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A particle is moving on a circular path ...

A particle is moving on a circular path of radius r with uniform speed v. What is the displacement of the particle after it has described an angle of `60^(@)`?

A

`rsqrt2`

B

`rsqrt3`

C

r

D

`2r`

Text Solution

Verified by Experts

The correct Answer is:
C
According to cosine formula
`cos60^(@)=(r^(2)+r^(2)-x^(2))/(2r^(2)`
`2r^(2)cos60^(@)=2r^(2)-x^(2)`
or, `x^(2)=2r^(2)-2r^(2) cos 60^(@)`
`=x^(2)=2r^(2)(1-cos 60^(@))`
`=2r^(2)xx2com^(2)30^(@)`
`=2r^(2)xx2xx(1)/(4)=r^(2)`
`bar(x=r)`
Displacement `AB=x=r`
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