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A stone tied to the end of string 100cm ...

A stone tied to the end of string 100cm long is whirled in a horizontal circle with a constant speed. If the stone makes 14 revolution in 22s, then the acceleration of the ston is

A

`16ms^(-2)`

B

`4ms^(-2)`

C

`12ms^(-2)`

D

`8ms^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
here `r=100 cm =1m`
Frequency `v=(14)/(22)Hz`
`:. Omega=2piv=2xx(22)/(7)xx(14)/(22)=4 "rads"^(-1)`
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