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When a body is projected from a level gr...

When a body is projected from a level ground the ratio of its speed in the vertical and horizontal direction is 4:3. If the velocity of projection is u, the time after which, the ratio of the velocities in the vertical and horizontal directions are reversed is (A)7u/20g (B)35u/10g (C)9u/g (D)10u/g

A

`(7u)/(20g)`

B

`(3u)/(10g)`

C

`(9u)/(20g)`

D

`(10u)/(7g)`

Text Solution

Verified by Experts

The correct Answer is:
A
given `(U_(y))/(U_(x))=4//3 rArr theta=53^(@)`
`(V_(y))/(V_(x))=3//4 rArr alpha=37^(@)C`
`U_(x)=V_(x) rArr (3u)/(5)=(4V)/(5), V=(3V)/(4)`
`V_(y)=U_(y)-"gt"`
`(3V)/(5)=(4U)/(5)-"gt"`
`"gt"=(4)/(5)-(3)/(5)xx(3u)/(4)=(7u)/(20) " " t=(7U)/(20g)`
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