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The horizontal range and miximum height ...

The horizontal range and miximum height attained by a projectile are `R and H`, respectively. If a constant horizontal acceleration `a = g//4` is imparted to the projectile due to wind, then its horizontal range and maximum height will be

A

`(R+H),H//2`

B

`(R+H//2),2H`

C

`(R+2H),H`

D

`(R+H),H`

Text Solution

Verified by Experts

The correct Answer is:
D
No change in maximum height
`R^(1)=V+1//2a+2`
`=R+(1)/(2)(g//4)+2`
`=R+(2^(2)sin^(2)theta)/(2g)`
`=R+H`
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