[" If the enthalpy of neutralisation of HC "/_" with "NaOH" is "x," the heat evolved when "500mi" of "],[250ml" of "4N" NaOH."]

To determine the enthalpy of neutralisation of HCl with NaOH we use

Enthalpy of neutralization of HCl with NaOH is X . The heat evolved when 500 ml of 2 N HCl is mixed with 250 ml of 4 N NaOH will be

Heat of neutralisation of H_2SO_4 with NaOH is - x KJ. Then the heat of ionisation of water is

Assertion : Enthalpy of neutralisation of 1 equivalent each of HCl and H_(2)SO_(4) with NaOH is same Reason : Enthalpy of neutralisation is always the heat evolved when 1 mole acid is neutralised by a base.

A: Enthalpy of neutralisation of 1 equivalent each of HCl and H_(2)SO_(4) with NaOH is same. R : Enthalpy of neutralisation is always the heat evolved when 1 mole acid is neutralised by a base.

A: Enthalpy of neutralisation of 1 equivalent each of HCI and H_(2)SO_(4) with NaOh is same. R : Enthalpy of neutralisation is always the heat evolved when 1 mole acis is neutralised by a base.