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[arctan x=1],[24*cos4x=1-8sin^(2)x cos^(...

[arctan x=1],[24*cos4x=1-8sin^(2)x cos^(2)x],[cos^(2)x-1]

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cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

cos 4x =1- 8 sin ^(2) x cos ^(2) x

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int (cos^(8)x-sin^(8)x)/(1-2 cos^(2)sin^(2)x)dx=

Prove that : cos 4x = 1 - 8 sin^2 x cos^2 x .