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A coil of inductane 0.2 henry is connect...

A coil of inductane `0.2` henry is connected to `600` volt battery. At what rate, will the current in the coil grow when circuit is completed ?

Text Solution

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As the battery and inductor are in parallel ,at any instant emf of the battery and self emf in the inductor are equal
`|e|=L(dI)/(dt)` or
`(dI)/(dt)=(|e|)/L=(600V)/(0.2H)=3000 A s^(-1)`
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