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A solenoid is of length 50 cm and has a ...

A solenoid is of length `50 cm` and has a radius of `2cm`. It has `500` turns. Around its central section a coil of `50` turns is wound. Calculate the mutual inductance of the system.

Text Solution

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`N_P=500,N_s=50, A =pixx0.02xx0.02m^2`
`mu_0=4pixx10^(-7)Hm^(-1),1=50 cm =0.5 m`
Now, `M=(mu_0N_PN_SA)/l`
`=(4pixx10^(-7)xx500xx50xxpixx(0.02)^2)/(0.5)H`
`=789.8 xx10^(-7)H=78.98muH`
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