Calculate the coefficient of self induction of a solenoid coil of 2000 turns, length 0.5 m and radius 5 cm , when the core is filled with
(i) air
(ii) soft iron `(mu_r= "for soft iron" =1000)`
N=2000 turns, l=0.5 m ,A = `pi(5 xx 10^(-2))^2`

Explanation

To calculate the coefficient of self-inductance of a solenoid coil, we can use the formula:

\[ L = \frac{\mu N^2 A}{l} \]

where:
- \(L\) = self-inductance
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