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An inductor of 3H is connected to a batt...

An inductor of `3H` is connected to a battery of emf `6V` through a resistance of `100 Omega`. Calculate the time constant. What will be the maximum value of current in the circuit ?

Text Solution

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Given that `L=3H, E=6V,R=100 Omega`
Time constant `tau_L=L/R=3/(100)=0.03` sec
Maximum current `I_0=E/R=6?(100)` amp=0.06 amp
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