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A coil having resistance 15 Omega and i...

A coil having resistance `15 Omega` and inductance `10H` is connected across a `90` Volt `dc` supply. Determine the value of current after `2sec`, What is the energy stored in the magnetic field at that instant.

Text Solution

Verified by Experts

Given that `R=15 Omega, L=10H, E=90` Volt
Peak value of current
`I_0=E/R=(90)/(15)A=6A` also, `tau_L=L/R=(10)/(15)=0.67` sec
Now, `I=I_0(1-e^((-Rt)/L))` , After 2 sec,
`I=6[1-e^(-2//0.67)]=6[1-0.05]=5.7A`
Energy stored in the magnetic field
`U=(1/2LI^2=1/2xx10xx95.7)^2J=162.45j`
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