The magnetic field perpendicular to the plane of a loop of area `0.1 m ^2` is 0.2 T . Calculate the magnetic flux through the loop (in weber)

Options

A. 0.01
B. 0.02
C. 0.03
D. 0.04

Explanation

To calculate the magnetic flux through the loop, we can use the formula for magnetic flux (Φ):

\[ Φ = B \cdot A \cdot \cos(θ) \]

Where:
- \(Φ\) is the magnetic flux in webers (Wb),
- \(B\) is the magnetic field strength in teslas (T),
- \(A\) is the area of the loop in square meters (m²),
- \(θ\) is the angle between the magnetic field and the normal (perpendicular) to the surface of the loop.

### Step 1: Identify the given values
- Area of the loop, \(A = 0.1 \, m²\)
- Magnetic field strength, \(B = 0.2 \, T\)
- Since the magnetic field is perpendicular to the plane of the loop, the angle \(θ = 0°\).

### Step 2: Calculate the cosine of the angle
\[ \cos(0°) = 1 \]

### Step 3: Substitute the values into the formula
Now, substituting the values into the magnetic flux formula:
\[ Φ = B \cdot A \cdot \cos(θ) \]
\[ Φ = 0.2 \, T \cdot 0.1 \, m² \cdot 1 \]

### Step 4: Perform the calculation
\[ Φ = 0.2 \cdot 0.1 = 0.02 \, Wb \]

### Conclusion
The magnetic flux through the loop is \(0.02 \, Wb\).

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