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In a magnetic field of 0.05T, area of a ...

In a magnetic field of `0.05T`, area of a coil changes from `101 cm^(2)` to `100 cm^(2)` without changing the resistance which is `2Omega`. The amount of charge that flow during this period is

A

`2.5 xx 10^(-6)`C

B

` 2xx 10^(-6)` C

C

`10^(-6)` C

D

`8 xx 10^(-8)` C

Text Solution

Verified by Experts

The correct Answer is:
A

(i)
`{:("Magnetic flux",phi=B*A),("Change in flux", dphi=B*dA):}`
`=0.05(101-100)10^-4=5xx10^-4Wb`
`:.` Charge
`dq=(dphi)/R=(5xx10^-6)/2=2.5xx10^-6C`
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