The horizontal component of the earth's ...

The horizontal component of the earth's magnetic field at a place is `3xx10^(-4)T` and the dip is `tan^(-1)((4)/(3))`. A metal rod of length `0.25m` placed in the north -south position and is moved at a constant speed of `10cm//s` towards the east. The emf induced in the rod will be

zero

1 mV

5 mV

10 mV

Text Solution

Verified by Experts

The correct Answer is:

`e=B_Vlvtantheta=B_V/B_H`

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