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A coil of 30 turns of wire each of 10 cm...

A coil of `30` turns of wire each of `10 cm^(2)` area is placed with its plance perpendicular to a magnetic field of `0.1 T`. When the coil is suddenly withdraw from the field, a galvanometer connected in series with the coil indicated that a `10 mu C` charge passes around the circuit. The combined resistance of the coil and galvanometer is

A

`3 Omega`

B

`30 Omega`

C

`300 Omega`

D

`3000 Omega`

Text Solution

Verified by Experts

The correct Answer is:
C
`q=(dphi)/R=(NA(B_1-B_2))/R`
`10 mu c=(30xx10^(-3)(0.1-0))/R, R=300 Omega`
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Knowledge Check

  • A coil of area 100 cm^(2) having 50turns is perpendicular to a magnetic field of intensity 0.02T. The resistance of the coil is 2Omega . If t is removed from magnetic field in is the charge flown through the coil is:

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