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A flexible wire loop in the shape of a c...

A flexible wire loop in the shape of a circle has a radius that grows linearly with time. There is a magnetic field perpendicular to the plane of the loop that has a magnitude inversely proportional to the distance from the centre of the loop, `B(r ) prop (1)/(r )` How does the `emf` `E` vary with time?

A

`E prop t^2`

B

`E prop t`

C

`E prop sqrtt`

D

E is constant

Text Solution

Verified by Experts

The correct Answer is:
D

Let radius of the loop is r at any time t and in further time dt radius increases by dr.

Then change in flux : `dphi=(2pirdr)B`
`rArr e=(dphi)/(dt)=2pir((dr)/(dt))k/r`
`rArr e=2pick ("constant") [therefore (dr)/(dt)=c,B=k/r]`
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